History: when zFS first came out, a recurring question was "Does CMOD work with zFS's?"
The answer was always yes. Completely transparent.
With z/OS V2.1 a new, and better format of zFS aggregate has been made available.
I'm not going to write about it, all one would want to know is here:
http://www-304.ibm.com/support/knowledgecenter/SSLTBW_2.1.0/com.ibm.zos.v2r1.ioea700/ioea7p02999476.htmRight now you can run the following JCL which simply does a brief display of information about each zFS aggregate on your system:
//AGGRINFO EXEC PGM=IOEZADM,REGION=0M,
// PARM=('aggrinfo -long')
//SYSPRINT DD SYSOUT=H
//STDOUT DD SYSOUT=H
//STDERR DD SYSOUT=H
//SYSUDUMP DD SYSOUT=H
//CEEDUMP DD SYSOUT=H
//* This is output for my V9.0 product zFS before converting it to the new format:
ARS.ARSV900.PRODUCT.ZFS (R/W COMP): 119662 K free out of total 1080000
version 1.4
auditfid E2D4E2E5 D3F20598 0000
14957 free 8k blocks; 6 free 1K fragments
2160 K log file; 56 K filesystem table
160 K bitmap file Note the "version 1.4" in the output above, that's the old format.
I went into my BPXPRMxx and changed that mount to this:
MOUNT FILESYSTEM('ARS.ARSV900.PRODUCT.ZFS')
MOUNTPOINT('/usr/lpp/ars/V9R0M0')
TYPE(ZFS)
MODE(RDWR) PARM('CONVERTTOV5') All I did was add the PARM statement and IPLed.
Voila - now when I run the aggrinfo job I get:
ARS.ARSV900.PRODUCT.ZFS (R/W COMP): 119662 K free out of total 1080000
version 1.5
auditfid E2D4E2E5 D3F20598 0000
converttov5
14957 free 8k blocks; 6 free 1K fragments
2160 K log file; 56 K filesystem table
160 K bitmap file I have converted all of my product zFS's and all of my temp and cache zFS's and run a test load through my system.
It works.
Ed